14x^2-+9x+1=0

Solution for 14x^2-+9x+1=0 equation:

14x^2-+9x+1=0

We add all the numbers together, and all the variables

14x^2+9x=0

a = 14; b = 9; c = 0;
Δ = b2-4ac
Δ = 92-4·14·0
Δ = 81
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$\sqrt{\Delta}=\sqrt{81}=9$
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(9)-9}{2*14}=\frac{-18}{28}
=-9/14
$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(9)+9}{2*14}=\frac{0}{28}
=0
$